广度优先遍历
小于 1 分钟
广度优先遍历 - 层序遍历
思路:
/**
* Definition for a binary tree node.
* class TreeNode {
* val: number
* left: TreeNode | null
* right: TreeNode | null
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
* }
*/
function levelOrder(root: TreeNode | null): number[][] {
if(!root){
return []
}
let ans = []
let cur = [root]
while(cur.length){
let nxt = []
let vals = []
for(const node of cur){
vals.push(node.val)
if(node.left) nxt.push(node.left)
if(node.right) nxt.push(node.right)
}
cur = nxt
ans.push(vals)
}
return ans
};